{"id":868,"date":"2023-05-25T17:22:13","date_gmt":"2023-05-25T20:22:13","guid":{"rendered":"https:\/\/proexatas.com\/?page_id=868"},"modified":"2023-05-25T18:08:58","modified_gmt":"2023-05-25T21:08:58","slug":"optica-geometrica","status":"publish","type":"page","link":"https:\/\/proexatas.com\/index.php\/optica-geometrica\/","title":{"rendered":"\u00d3ptica Geom\u00e9trica"},"content":{"rendered":"\n<h4 class=\"wp-block-heading has-text-align-center\"><strong><em>Princ\u00edpios da \u00d3ptica Geom\u00e9trica<\/em><\/strong><\/h4>\n\n\n<hr>\n<p style=\"text-align: justify;\"><strong>Q-01) <\/strong><em><strong>(Famema SP\/2023) <\/strong><\/em>Dois feixes de luz, A e B, de frequ\u00eancias iguais a f<sub>A<\/sub> = 4f e f<sub>B<\/sub> = 6f, cruzam-se em determinado ponto do espa\u00e7o, seguindo seus caminhos originais ap\u00f3s o cruzamento. De acordo com os princ\u00edpios da \u00f3ptica, as frequ\u00eancias dos feixes A e B, ap\u00f3s o cruzamento s\u00e3o, respectivamente,<\/p>\n<p>a) 6f e 4f.<\/p>\n<p>b) 2f e 3f.<\/p>\n<p>c) 4f e 6f.<\/p>\n<p>d) 10f e 10f.<\/p>\n<p>e) 5f e 5f.<\/p>\n\n\n<div id=\"wp-block-themeisle-blocks-accordion-c0d21da4\" class=\"wp-block-themeisle-blocks-accordion exclusive\">\n<details class=\"wp-block-themeisle-blocks-accordion-item\"><summary class=\"wp-block-themeisle-blocks-accordion-item__title\"><div>Visualizar alternativa correta \/ coment\u00e1rio da quest\u00e3o<\/div><\/summary><div class=\"wp-block-themeisle-blocks-accordion-item__content\">\n<p class=\"wp-block-paragraph\"><strong>Alternativa correta (C)<\/strong> &#8211; As frequ\u00eancias n\u00e3o se alteram uma vez que dependem das fontes que geraram os feixes de luz.<\/p>\n<\/div><\/details>\n<\/div>\n\n\n<p style=\"text-align: justify;\"><strong>Q-02) <\/strong><em><strong>(Famerp SP\/2019) <\/strong><\/em>A figura mostra uma l\u00e2mpada retil\u00ednea, de comprimento 90 cm, fixa horizontalmente no teto de uma sala, 200 cm acima da superf\u00edcie plana e horizontal de uma mesa. Um disco circular opaco foi colocado horizontalmente entre a l\u00e2mpada e a mesa, a 180 cm da l\u00e2mpada, sendo esta a maior dist\u00e2ncia para que ele n\u00e3o projete sombra sobre a mesa. A reta r, mostrada na figura, \u00e9 vertical e passa pelo ponto m\u00e9dio da l\u00e2mpada e pelo centro do disco.<\/p>\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/proexatas.com\/wp-content\/uploads\/2023\/05\/optica-01.png\" alt=\"\" class=\"wp-image-884\" width=\"420\" height=\"330\" srcset=\"https:\/\/proexatas.com\/wp-content\/uploads\/2023\/05\/optica-01.png 672w, https:\/\/proexatas.com\/wp-content\/uploads\/2023\/05\/optica-01-600x471.png 600w, https:\/\/proexatas.com\/wp-content\/uploads\/2023\/05\/optica-01-300x236.png 300w\" sizes=\"auto, (max-width: 420px) 100vw, 420px\" \/><\/figure>\n<\/div>\n\n<p>Calcule o di\u00e2metro do disco, em cent\u00edmetros.<\/p>\n\n\n<div id=\"wp-block-themeisle-blocks-accordion-3fa7ce00\" class=\"wp-block-themeisle-blocks-accordion exclusive\">\n<details class=\"wp-block-themeisle-blocks-accordion-item\"><summary class=\"wp-block-themeisle-blocks-accordion-item__title\"><div>Visualizar alternativa correta \/ coment\u00e1rio da quest\u00e3o<\/div><\/summary><div class=\"wp-block-themeisle-blocks-accordion-item__content\">\n<p class=\"wp-block-paragraph\">Utilizando semelhan\u00e7a de tri\u00e2ngulos podemos demonstrar que o di\u00e2metro do disco \u00e9 igual a 9,0 cent\u00edmetros.<\/p>\n<\/div><\/details>\n<\/div>\n\n\n<p style=\"text-align: justify;\"><strong>Q-03) <\/strong><em><strong>(Unesp SP\/2011) <\/strong><\/em>Para que algu\u00e9m, com o olho normal, possa distinguir um ponto separado de outro, \u00e9 necess\u00e1rio que as imagens desses pontos, que s\u00e3o projetadas em sua retina, estejam separadas uma da outra a uma dist\u00e2ncia de 0,005 mm.<\/p>\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/proexatas.com\/wp-content\/uploads\/2023\/05\/optica-02.png\" alt=\"\" class=\"wp-image-890\" width=\"493\" height=\"222\" srcset=\"https:\/\/proexatas.com\/wp-content\/uploads\/2023\/05\/optica-02.png 737w, https:\/\/proexatas.com\/wp-content\/uploads\/2023\/05\/optica-02-600x270.png 600w, https:\/\/proexatas.com\/wp-content\/uploads\/2023\/05\/optica-02-300x135.png 300w\" sizes=\"auto, (max-width: 493px) 100vw, 493px\" \/><\/figure>\n<\/div>\n\n<p style=\"text-align: justify;\">Adotando-se um modelo muito simplificado do olho humano no qual ele possa ser considerado uma esfera cujo di\u00e2metro m\u00e9dio \u00e9 igual a 15 mm, a maior dist\u00e2ncia x, em metros, que dois pontos luminosos, distantes 1 mm um do outro, podem estar do observador, para que este os perceba separados, \u00e9<\/p>\n<p>a) 1.<\/p>\n<p>b) 2.<\/p>\n<p>c) 3.<\/p>\n<p>d) 4.<\/p>\n<p>e) 5.<\/p>\n\n\n<div id=\"wp-block-themeisle-blocks-accordion-63e858b6\" class=\"wp-block-themeisle-blocks-accordion exclusive\">\n<details class=\"wp-block-themeisle-blocks-accordion-item\"><summary class=\"wp-block-themeisle-blocks-accordion-item__title\"><div>Visualizar alternativa correta \/ coment\u00e1rio da quest\u00e3o<\/div><\/summary><div class=\"wp-block-themeisle-blocks-accordion-item__content\">\n<p class=\"wp-block-paragraph\"><strong>Alternativa correta (C)<\/strong> &#8211; Pode-se resolver o item por semelhan\u00e7a de tri\u00e2ngulos.<\/p>\n<\/div><\/details>\n<\/div>\n\n\n<p style=\"text-align: justify;\"><strong>Q-04) <\/strong><em><strong>(Unesp SP\/2009) <\/strong><\/em>Um pai, desejando brincar com seu filho com a sombra de um boneco projetada na parede, acende uma l\u00e2mpada, considerada uma fonte de luz puntiforme, distante 2 metros do boneco e 6 metros da parede na qual a sombra ser\u00e1 projetada.\u00a0Admitindo que a altura do boneco seja igual a 20 cm, qual a altura da sombra projetada na parede? Fa\u00e7a um desenho, na folha de respostas, representando os raios de luz a partir da l\u00e2mpada at\u00e9 a parede e indicando a posi\u00e7\u00e3o do boneco e a regi\u00e3o de sombra.<\/p>\n\n\n<div id=\"wp-block-themeisle-blocks-accordion-7c8ae0dd\" class=\"wp-block-themeisle-blocks-accordion exclusive\">\n<details class=\"wp-block-themeisle-blocks-accordion-item\"><summary class=\"wp-block-themeisle-blocks-accordion-item__title\"><div>Visualizar alternativa correta \/ coment\u00e1rio da quest\u00e3o<\/div><\/summary><div class=\"wp-block-themeisle-blocks-accordion-item__content\">\n<p class=\"wp-block-paragraph\">Utilizando semelhan\u00e7a de tri\u00e2ngulos, a altura da sombra projetada na parede ser\u00e1 de 60 cent\u00edmetros.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/proexatas.com\/wp-content\/uploads\/2023\/05\/optica-03.png\" alt=\"\" class=\"wp-image-891\" width=\"444\" height=\"356\" srcset=\"https:\/\/proexatas.com\/wp-content\/uploads\/2023\/05\/optica-03.png 763w, https:\/\/proexatas.com\/wp-content\/uploads\/2023\/05\/optica-03-600x481.png 600w, https:\/\/proexatas.com\/wp-content\/uploads\/2023\/05\/optica-03-300x241.png 300w\" sizes=\"auto, (max-width: 444px) 100vw, 444px\" \/><\/figure>\n<\/div><\/div><\/details>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Princ\u00edpios da \u00d3ptica Geom\u00e9trica Q-01) (Famema SP\/2023) Dois feixes de luz, A e B, de frequ\u00eancias iguais a fA = 4f e fB = 6f, cruzam-se em determinado ponto do espa\u00e7o, seguindo seus caminhos originais ap\u00f3s o cruzamento. De acordo com os princ\u00edpios da \u00f3ptica, as frequ\u00eancias dos feixes A [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"_themeisle_gutenberg_block_has_review":false,"footnotes":""},"class_list":["post-868","page","type-page","status-publish","hentry"],"jetpack_sharing_enabled":true,"_links":{"self":[{"href":"https:\/\/proexatas.com\/index.php\/wp-json\/wp\/v2\/pages\/868","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/proexatas.com\/index.php\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/proexatas.com\/index.php\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/proexatas.com\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/proexatas.com\/index.php\/wp-json\/wp\/v2\/comments?post=868"}],"version-history":[{"count":11,"href":"https:\/\/proexatas.com\/index.php\/wp-json\/wp\/v2\/pages\/868\/revisions"}],"predecessor-version":[{"id":893,"href":"https:\/\/proexatas.com\/index.php\/wp-json\/wp\/v2\/pages\/868\/revisions\/893"}],"wp:attachment":[{"href":"https:\/\/proexatas.com\/index.php\/wp-json\/wp\/v2\/media?parent=868"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}